NTA Abhyas JEE Main2020MathematicsVector AlgebraPractice
Let a → = x 2 i ^ - 3 j ^ + x + 3 k ^ and b → = i ^ + 3 j ^ - x - 3 k ^ be two vectors such that a → = b → . If angle between 4 a → + 7 b → and 7 a → - 4 b → is equal to θ , then cos 2 θ is equal to
Options
- A- 1 2
- B3 2
- C- 1
- D1 5
Correct answer
C. - 1
Step-by-step solution
∵ a → · b → = x 2 - 9 - x 2 - 9 = 0 ⇒ a → ⊥ b → 4 a → + 7 b → ⋅ 7 a → − 4 b → = 28 a → 2 − 28 b → 2 + 33 a → ⋅ b → = 0   as  a → = b → ⇒ θ = 90 o ⇒ cos ⁡ 2 θ = - 1