NTA Abhyas JEE Main2020MathematicsVector AlgebraPractice
The value of a , such that the volume of the parallelopiped formed by the vectors i ^ + j ^ + k ^ , j ^ + a k ^ and a i ^ + k ^ becomes minimum, is
Options
- A3
- B- 1 3
- C1 2
- D- 2
Correct answer
C. 1 2
Step-by-step solution
Volume of parallelopiped = a → b → c → Here, the parallelopiped is formed by the vectors i ^ + j ^ + k ^ , j ^ + a k ^ and a i ^ + k ^ So, the volume, V = 1 1 1 0 1 a a 0 1 = 1 + a 2 - a = 3 4 + a - 1 2 2 cubic units Hence, the volume of the parallelopiped is minimum when a = 1 2