NTA Abhyas JEE Main2020MathematicsVector AlgebraPractice
If a → = 2 i ^ − 3 j ^ + 4 k ^ ,   a → ⋅ b → = 2 and a → × b →   = i ^ + 2 j ^ + k ^ , then b → is equal to
Options
- A15 i ^ - 8 j ^ + k ^
- B1 29 15 i ^ - 8 j ^ + k ^
- C1 5 2 i ^ + j ^ + k ^
- D2 i ^ + j ^ + k ^
Correct answer
B. 1 29 15 i ^ - 8 j ^ + k ^
Step-by-step solution
a → × b → = i ^ + 2 j ^ + k ^ Taking cross product with a → on both the sides, we get, a → × b → × a → = i ^ + 2 j ^ + k ^ × a → ⇒ a → ⋅ a → b → − b → ⋅ a → a → = i ^ j ^ k ^ 1 2 1 2 − 3 4 ⇒ 29 b → - 2 a → = i ^ 11 - j ^ 2 + k ^ - 7 ⇒ 29 b → = 15 i ^ - 8 j ^ + k ^ ⇒ b → = 1 29 15 i ^ - 8 j ^ + k ^