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NTA Abhyas JEE Main2020MathematicsVector AlgebraPractice

If x → and y → be two non-collinear vectors and a triangle A B C with side lengths a , b , c satisfy the vector equation 20 a - 15 b x → + 15 b - 12 c y → + 12 c - 20 a x → × y → = 0 → , then ∆ A B C is

Options

  1. Aan acute angle triangle
  2. Ban obtuse angle triangle
  3. Ca right angle triangle
  4. Dan isosceles triangle.

Correct answer

C. a right angle triangle

Step-by-step solution

∵ x → , y → and x → × y → are non coplanar vectors 20 a - 15 b = 0 , 15 b - 12 c = 0 , 12 c - 20 a = 0 ⇒ a 3 = b 4 = c 5 ⇒ ∆ A B C is a right angle triangle

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