NTA Abhyas JEE Main2020PhysicsAlternating CurrentPractice
In the adjacent circuit, the instantaneous current equation is
Options
- A2 sin 100 t - π 4
- B2 sin 100 t - π 4
- C2 sin 200 t - π 4
- D2 100 t + π 4
Correct answer
B. 2 sin 100 t - π 4
Step-by-step solution
Let ϕ is the phase difference between V and i tan ϕ = X L R = ω L R = 100 × 1 100 =1 ⇒ θ = π 4 Since this is an LR circuit V will lead i ∴ Instantaneous current equation will be i = i 0 sin 100 t - ϕ where ϕ = π 4 and i 0 = V 0 Z i 0 = V 0 R 2 + ω L 2 = 200 100 2 + 100 × 1 2 = 2 ∴ i = 2 sin 100 t - π 4