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NTA Abhyas JEE Main2020PhysicsAlternating CurrentPractice

In a series LCR circuit, the voltage drop across the resistance is 8 V , across the inductor is 6 V and across the capacitor is 12 V . Then,

Options

  1. Athe voltage of the source will be leading the current in the circuit
  2. Bthe voltage drop across each element will be less than the applied voltage
  3. Cthe power factor of the circuit will be 4 3
  4. Dnone of these

Correct answer

D. none of these

Step-by-step solution

Since, cos ⁡ ϕ = R Z = I R I Z = 8 10 = 4 5 (Also cos ⁡ ϕ can never be greater than 1 ) Hence, (c) is wrong Also I X C > I X L ⇒ X C > X L ∴ Current will be leading. In an LCR circuit, V = V L - V C 2 + V R 2 = 6 - 12 2 + 8 2 V = 10 V , which is less than the voltage drop across the capacitor.

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