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NTA Abhyas JEE Main2020PhysicsAlternating CurrentPractice

In the given circuit the R.M.S. values of voltages across the capacitor C , inductor L and resistor R 1 are 12 V , 10 V and 5 V respectively. Then the peak voltage across R 2 is

Options

  1. A7 2   V
  2. B69   V  
  3. C138 V
  4. Dnone of these

Correct answer

C. 138 V

Step-by-step solution

In a parallel combination, each branch should have equal potential. But in AC circuit, in a branch, V eff = V R 2 + ( V c - V L ) 2 V C 2 + V R 1 2 = V L 2 + V R 2 2 ⇒ 12 2 + 5 2 = 10 2 + V R 2 2   ⇒ ( V R 2 ) rms = 69 V peak = 2 V rms ∴ V R 2 peak = 138   V

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