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NTA Abhyas JEE Main2020PhysicsAlternating CurrentPractice

An inductor coil and a capacitor and a resistance of 5 Ω are connected in series to an a.c. source of rms voltage 30 V. When the frequency of the source is varied, a maximum r.m.s. current of 5 A is observed. If this inductor is connected in parallel with a resistance 5 Ω to a battery of emf 25 V and internal resistance 2.0 Ω , the current drawn from the battery is

Options

  1. A1 5 0 1 7 A
  2. B2.5 A
  3. C1 2 5 3 3 A
  4. D1 2 5 9 9 A

Correct answer

A. 1 5 0 1 7 A

Step-by-step solution

Let resistance of inductor be μ I max = 3 0 5 + μ = 5 ⇒ μ = 1 Ω Now, I = 2 5 5 6 + 2 = 1 5 0 1 7 A

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