NTA Abhyas JEE Main2020PhysicsAlternating CurrentPractice
An AC e.m.f E = 4 cos 1000 t V is applied to an L R circuit containing inductance 3 m H and resistance 4 Ω . The amplitude of the current is
Options
- A4 7   A
- B1.0 A
- C4 7   A
- D0.8 A
Correct answer
D. 0.8 A
Step-by-step solution
i 0 = V 0 Z   , Z = R 2 + ω L 2 = 4 2 + 1000 × 3 × 1 0 - 3 2 = 5   Ω i 0 = 4 5 i 0 = 0.8  A