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The shortest wavelength of the Brackett series of a hydrogen like atom (Atomic number = Z ) is the same as the shortest wavelength of the Balmer series of hydrogen atom. The value of Z is

Options

  1. A2
  2. B3
  3. C4
  4. D6

Correct answer

A. 2

Step-by-step solution

Shortest wavelength corresponds to maximum energy therefore transitions are from infinity to n = 4 and n = 2 respectively. Z 2 13.6 16 = 13.6 4 Z 2 = 4 or Z = 2

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