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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Atomic Physics

NTA Abhyas 2020 · Physics · Atomic Physics

Electrons in a certain energy level n = n _ 1 , can emit 3 spectral...

Electrons in a certain energy level n=n1n = {n }_{1}, can emit 33 spectral lines. When they are in another energy level, n=n2n = {n }_{2}, they can emit 66 spectral lines. The ratio of orbital speeds of the electrons is

Options

  1. A4:34: 3
  2. B3:43: 4
  3. C2:12: 1
  4. D1:21: 2

Correct answer

A. 4:34: 3

Step-by-step solution

Number of emitted spectral lines, N=n(n−1)2N = \dfrac{n ( n - 1 )}{2}.

Case I
N=3N = 3
⇒3=n1(n1−1)2⇒ 3 = \dfrac{{n}_{1} ( {n}_{1} - 1 )}{2}
⇒n12−n1−6=0⇒ {n}_{1}^{2} - {n}_{1} - 6 = 0
⇒(n1−3)(n1+2)=0⇒ ( {n}_{1} - 3 ) ( {n}_{1} + 2 ) = 0
⇒n1=3⇒ {n}_{1} = 3

Case II

N=6N = 6
⇒6=n2(n2−1)2⇒ 6 = \dfrac{{n}_{2} ( {n}_{2} - 1 )}{2}
⇒n22−n2−12=0⇒ {n2}^{2} - {n}_{2} - 12 = 0
⇒(n2−4)(n2+3)=0⇒ ( {n}_{2} - 4 ) ( {n}_{2} + 3 ) = 0
⇒n2=4⇒ {n}_{2} = 4

Velocity of electron v=Ze22ε0hnv = \dfrac{{Ze}^{2}}{2{ε}_{0}hn}
∴v1v2=n2n1∴ \dfrac{v1}{v2} = \dfrac{n2}{n1}
⇒v1v2=43⇒ \dfrac{v1}{v2} = \dfrac{4}{3}

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