The shortest wavelength of Lyman series of hydrogen atom is equal...

The shortest wavelength of Lyman series of hydrogen atom is equal to the shortest wavelength of Balmer series of an hydrogen like atom of atomic number

Z

. The value of

Z

is equal to

Options

A $2$
B $3$
C $4$
D $6$

Correct answer

A. $2$

Step-by-step solution

13.6\left(Z^{2}\right)\left(\dfrac{1}{{2}^{2}} - \dfrac{1}{\infty}\right) = 13.6 \left(\dfrac{1}{{1}^{2}} - \dfrac{1}{{\infty}^{2}}\right)<br /><br />

⇒ Z = 2

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