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The shortest wavelength of Lyman series of hydrogen atom is equal to the shortest wavelength of Balmer series of an hydrogen like atom of atomic number Z . The value of Z is equal to

Options

  1. A2
  2. B3
  3. C4
  4. D6

Correct answer

A. 2

Step-by-step solution

13.6 Z 2 1 2 2 - 1 ∞ = 13.6 1 1 2 - 1 ∞ 2 ⇒ Z = 2

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