The K _ α line obtained for molybdenum ( Z = 42 ) is 0.71 Å . Then, the wavelength of the K _ α line of copper ( Z = 29 ) is

Correct answer: B. 1.52Å λ _ ∝ 1 (Z - 1)^ 2 ∴ λ _ Cu λ _ Mo = ( Z _ Mo - 1) ^ 2 ( Z _ Cu - 1) ^ 2 = 4 1 ^ 2 (2 8) ^ 2 = 2.14 ∴ λ _ Cu = 2.14 × 0.71 Å = 1.52 Å

NTA Abhyas 2020

Exam: NTA Abhyas
Year: 2020
Subject: Physics
Chapter: Atomic Physics

NTA Abhyas 2020 · Physics · Atomic Physics

The K _ α line obtained for molybdenum ( Z = 42 ) is 0.71 Å . Then,...

The

{K}_{α}

line obtained for molybdenum

( Z = 42 )

0.71 Å

. Then, the wavelength of the

{K}_{α}

line of copper

( Z = 29 )

Options

A $\text{2.14}Å$
B $\text{1.52}Å$
C $\text{1.04}Å$
D $\text{0.71}Å$

Correct answer

B. $\text{1.52}Å$

Step-by-step solution

{λ}_\min ∝ \dfrac{1}{\left(\text{Z} - 1\right)^{2}}

∴ \dfrac{{λ}_{Cu}}{{λ}_{Mo}} = \dfrac{{\left({Z}_{Mo} - 1\right)}^{2}}{{\left({Z}_{Cu} - 1\right)}^{2}} = \dfrac{4 {1}^{2}}{{\left(2 8\right)}^{2}} = \text{2.14}

∴ {λ}_{Cu} = \text{2.14} \times 0.71 Å = 1.52 Å

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