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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Atomic Physics

NTA Abhyas 2020 · Physics · Atomic Physics

Which among the following has a Hydrogen-like spectrum and whose...

Which among the following has a Hydrogen-like spectrum and whose lines have wavelengths four times shorter than those of atomic Hydrogen?

Options

  1. AHelium ion
  2. BBeryllium ion
  3. CLithium ion
  4. DNone of these

Correct answer

A. Helium ion

Step-by-step solution

For Hydrogen like atom, 1λ′=RZ2(1n12−1n22)...(i)<br/><br/>ForHydrogenatom,1λ=R(1n12−1n22)...(ii)<br/><br/>DividingEqn(ii)byEqn(i),weget<br/><br/>λ′λ=R(1n12−1n22)RZ2(1n12−1n22)\dfrac{1}{\lambda '}=R Z{}^{2} \left(1{n}_{1}^{2} - 1{n}_{2}^{2}\right) ...(i)<br /><br />For Hydrogen atom, \dfrac{1}{λ}= R \left(1{n}_{1}^{2} - 1{n}_{2}^{2}\right) ...(ii)<br /><br />Dividing Eqn (ii) by Eqn (i), we get<br /><br /> \dfrac{\lambda '}{λ} =\dfrac{R \left(1{n}_{1}^{2} - 1{n}_{2}^{2}\right)}{{RZ}^{2}\left(1{n}_{1}^{2} - 1{n}_{2}^{2}\right)}

orλ′λ=1Z2\text{or}\dfrac{\lambda '}{λ} =\dfrac{1}{Z{}^{2}}

According to problem, λ′=λ4{λ}^{'} = \dfrac{λ}{4}

∴ λ′4λ′=1Z2\dfrac{\lambda '}{4{λ}^{'}} = \dfrac{1}{Z{}^{2}}

∴Z=2∴ Z = 2

The atomic number of Helium atom is 22. Hence, the required element is Helium.

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