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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Atomic Physics

NTA Abhyas 2020 · Physics · Atomic Physics

A hydrogen-like atom (atomic number Z ) is in a higher excited...

A hydrogen-like atom (atomic number ZZ) is in a higher excited state of quantum number nn. This excited atom can make a transition to the first excited state by successively emitting two photons of energies 10.20eV\text{10.20}eV and 17.00eV\text{17.00}eV respectively. Alternatively, the atom from the same excited state can make a transition to the second excited state by successively emitting two photons of energy 4.25eV\text{4.25}eV and 5.95eV\text{5.95}eV respectively. Determine the value of ZZ. [Ionization energy of hydrogen atom =13.6eV]= \text{13.6}eV]A hydrogen-like atom (atomic number Z ) is in a higher excited state of quantum number n . This excited atom can make a

Correct answer

3

Step-by-step solution

A hydrogen-like atom (atomic number Z ) is in a higher excited state of quantum number n . This excited atom can make a

10.2+17=13.6×Z2(122−1n2);4.25+5.95=13.6×Z2(132−1n2)\text{10.2} + 17 = \text{13.6} \times {Z}^{2}\left(\dfrac{1}{{2}^{2}} - \dfrac{1}{{n}^{2}}\right); \text{4.25} + \text{5.95} = \text{13.6} \times {Z}^{2}\left(\dfrac{1}{{3}^{2}} - \dfrac{1}{{n}^{2}}\right)

Solving the above two equation we get, Z=3Z = 3 and n=6n = 6.
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