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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Atomic Physics

NTA Abhyas 2020 · Physics · Atomic Physics

If ∆ r _ 1 represents the difference in radii of stationary orbits&...

If ∆r1∆ {r}_{1} represents the difference in radii of stationary orbits& for& n=3n = 3 and n=4n = 4 in a hydrogen atom and ∆r2∆ {r}_{2} represents the difference in radii of stationary orbits for& n=8n = 8 and n=9n = 9, then the value of ∆r1∆r2\dfrac{∆ {r}_{1}}{∆ {r}_{2}}& is

Options

  1. A0.71\text{0.71}
  2. B0.410.41
  3. C2.43\text{2.43}
  4. D14.82\text{14.82}

Correct answer

B. 0.410.41

Step-by-step solution

Use the relationship between the radius of an orbit and quantum number nn of that orbit.

r4−r3r9−r8=r1×42−r1×32r1×92−r1×82=16−981−64=0.41\dfrac{{r}_{4} - {r}_{3}}{{r}_{9} - {r}_{8}} = \dfrac{{r}_{1} \times {4}^{2} - {r}_{1} \times {3}^{2}}{{r}_{1} \times {9}^{2} - {r}_{1} \times {8}^{2}} = \dfrac{16 - 9}{81 - 64} = 0.41
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