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An electron in a hydrogen atom makes a transition from n = 2 to n = 1 and emits a photon. This photon strikes a doubly ionized lithium atom which was already in an excited state and completely removes the orbiting electron. The least quantum number for the excited state of the lithium-ion for the process is

Options

  1. A2
  2. B4
  3. C5
  4. D3

Correct answer

B. 4

Step-by-step solution

Let us assume that the electron in the lithium-ion is knocked off from the n th energy level, then R Z H 2 1 1 2 − 1 2 2 = R Z Li 2 n 2 R 1 2 × 3 4 = R 3 2 1 n 2 3 4 = 9 n 2 n = 12 ≈ 3 . 5 Hence the least quantum number must be 4 .

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