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The shortest wavelength of the Brackett series of a hydrogen like atom of atomic number Z is same as the shortest wavelength of the Balmer series of hydrogen atom, then the value of Z is

Correct answer

2

Step-by-step solution

Shortest wavelength of Brackett corresponds to n = 4 and n = ∞ and shortest wavelength of Balmer series corresponds to n = 2 and n = ∞ ∴ Z 2 13.6 16 = 13.6 16 ⇒ Z = 2

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