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The wavelength of a photon and de-Broglie wavelength an electron have the same value. Given that v is the speed of electron and c is the velocity of light. E e , E p is the kinetic energy of electron and energy of photon respectively while p e , p h is the momentum of electron and photon respectively. Then which of the following relation is correct?

Options

  1. AE e E p = v 2 c
  2. BE e E p = 2 c v
  3. Cp e p h = c 2 v
  4. Dp e p h = 2 c v

Correct answer

A. E e E p = v 2 c

Step-by-step solution

E e = 1 2 m v 2 = 1 2 m v v = 1 2 h λ v and E p = h c λ ; ∴ E e E p = v 2 c and according to De Broglie's equation p h = h λ ∴ p e p h = 1

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