An electron in a hydrogen atom is in an orbit from which there can be a maximum of six transitions. Another electron in a different hydrogen atom is in an orbit from which there can be a maximum of three transitions. The ratio of the velocities of the electrons in these two orbits is

Step-by-step solution

Number of spectral lines obtained due to transition of electrons from n t h orbit to lower orbit is,   N = n ( n - 1 ) 2 For case - 1, N = 6   = n 1 ( n 1 - 1 ) 2 ⇒                                 n 1 = 4 For case - 2, N = 3   = n 2 ( n 2 - 1 ) 2 ⇒                                 n 2 = 3 The velocity of electron in a hydrogen atom