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According to Bohr's model, the minimum energy (in eV ) required to remove an electron from the ground state of a doubly ionized Li atom Z = 3 is

Options

  1. A40 . 8
  2. B13
  3. C122 . 4
  4. D1 . 51

Correct answer

C. 122 . 4

Step-by-step solution

The doubly ionized Li atom is H -like atom E n = - 13.6 Z 2 n 2   eV The ground state energy of the doubly ionised Li atom ( Z   =   3 ,   n   =   1 ) will be E 1 = - 13.6 × 9 1 = - 122.4   eV Hence, the ionisation energy for an electron in the ground state of doubly ionised Li atom = 122.4   eV

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