An alpha nucleus of energy 1 2 m v 2 bombards on a heavy nuclear target of the charge Ze . Then the distance of closest approach for the alpha nucleus will be proportional to

Step-by-step solution

For the closest approach, kinetic energy is converted into potential energy         1 2 mv 2 = 1 4 π ε 0 q 1 q 2 r 0 = 1 4 π ε 0 Ze 2 e r 0 r 0 ∝ Z v 2