A hydrogen atom is in the ground state. Then to get six lines in the emission spectrum, the wavelength of incident radiation should be ( Rydberg constant R = 1 . 1 × 10 7 m - 1 )

Step-by-step solution

Number of possible spectral lines emitted when an electron jumps back to the ground state from n t h orbit = n ( n − 1 ) 2 Here, n ( n − 1 ) 2 = 6 ⇒ n = 4 Wavelength λ from the transition from n = 1 to n = 4 is given by, 1 λ = R ( 1 1 − 1 4 2 ) ⇒ λ = 16 15 R = 975   A ∘