NTA Abhyas JEE Main2020PhysicsAtomic PhysicsPractice
A potential difference of 20 kV is applied across an X-ray tube. The minimum wavelength of X-rays generated is
Options
- A0.84 Å
- B0.31 Å
- C0.62 Å
- D0.96 Å
Correct answer
C. 0.62 Å
Step-by-step solution
E = h c λ ∴ λ min = h c e V = 6 . 6 3 × 1 0 - 3 4 × 3 × 1 0 8 1 . 6 × 1 0 - 1 9 × 2 0 × 1 0 3 = 0 . 6 2 A o