NTA Abhyas JEE Main2020PhysicsAtomic PhysicsPractice
The angular momentum of an electron in Bohr's hydrogen atom whose energy is - 3.4 eV, is
Options
- A5 h 2 π
- Bh 2 π
- Ch π
- D2 h 3 π
Correct answer
C. h π
Step-by-step solution
The energy of an electron in nth orbit of a hydrogen atom is given by E n =   - 13.6 n 2   eV ⇒           3.4 = - 13.6 n 2 ⇒       n 2 = 4 ⇒       n = 2 The angular momentum of electron is given by L = n h 2 π = 2 h 2 π = h π