NTA Abhyas JEE Main2020PhysicsDual Nature of MatterPractice
The maximum kinetic energy of photoelectrons emitted from a metal surface increases from 0 . 4   eV to 1 . 2   eV when the frequency of the incident radiation is increased by 40 % . What is the work function (in eV ) of the metal surface?
Correct answer
1.6
Step-by-step solution
According to Einstein's photoelectric equation, K max = h υ - ϕ 0 where K max is the maximum kinetic energy of photoelectrons and ϕ 0 is the work function of the metal surface Initially, h υ = 0 . 4 + ϕ 0 When the frequency is increased by 40 % , then 1 . 4 h υ = 1 . 2 + ϕ 0 On solving we get ϕ 0 = 1 . 6   eV