NTA Abhyas JEE Main2020PhysicsDual Nature of MatterPractice
In a photoelectric experiment, the wavelength of the light incident on a metal is changed from 300 nm to 400 nm . Choose the closest value of change in the stopping potential from given options h c e = 1240 nm · V
Options
- A2 . 0   V
- B0 . 5   V
- C1 . 0   V
- D1 . 5   V
Correct answer
C. 1 . 0   V
Step-by-step solution
v s 1 = 1240 300 - ϕ v s 2 = 1240 400 - ϕ v s 1 - v s 2 = 1240 300 - 1240 400 = 4 . 13 - 3 . 1 = 1 . 03 = 1