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A metal surface, having work function ϕ = 2 . 2 × 10 - 19 J , is illuminated by a light of wavelength 1320 A o . The maximum kinetic energy (in eV ) of the emitted photoelectron is [Take h = 6 . 6 × 10 - 34 J s ]

Correct answer

8

Step-by-step solution

K . E · = hc λ - ϕ 0 = 6 . 6 × 10 - 34 × 3 × 10 8 1320 × 10 - 10 - 2 . 2 × 10 - 19 = 15 × 10 - 19 - 2 . 2 × 10 - 19 = 12 . 8 × 10 - 19 J K . E · = 12 . 8 × 10 - 19 1 . 6 × 10 - 19 eV = 8 eV

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