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The de-Broglie wavelength of an electron, α - particle and proton all having the same kinetic energy is respectively given as λ e , λ α a n d λ p . Then which of the following is not true?

Options

  1. Aλ e < λ p
  2. Bλ p > λ α
  3. Cλ e > λ α
  4. Dλ α < λ p < λ e

Correct answer

A. λ e < λ p

Step-by-step solution

de-Broglie wavelength &#955; = h m v = h 2 m E &#160; &#160; &#160; &#160; &#160; &#8658; &#955; &#8733; 1 m &#8756; &#160; &#160; &#160; &#160; &#955; e &#8733; 1 m e , &#160; &#160; &#160; &#955; &#945; &#160; &#8733; 1 m &#945; &#160; &#160; a n d &#160; &#955; p &#8733; 1 m p &#160; &#160; &#160; &#160; &#160; As we know that &#160; m e &#60; m p &#60; m &#945; So, &#955; e &#160; &#62; &#955; p &#62; &#955; &#945; Or &#955; e &#62; &#955; &#945; &#160; &#160; &#160; &#160; &#160; or &#955; p &#62; &#955; &#945

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