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The electric field associated with a light wave is given by E = E 0 sin ⁡ 1.57 × 10 7 x - c t (where x and t are in metre and second respectively). The stopping potential when this light is used in an experiment on photoelectric effect with the emitter having work function ϕ = 1.9 e V is.

Options

  1. A0.6 e V
  2. B1.2 e V
  3. C1.8 e V
  4. D2.4 e V

Correct answer

B. 1.2 e V

Step-by-step solution

Given, E = E 0 sin ⁡ 1.57 × 10 7 x - c t ...(i) ∴ E = E 0 sin ⁡ ω c x - c t ...(ii) On comparing Equations (i) and (ii), we get ω c = 1.57 × 10 7 = π 2 × 10 7 λ = 4 × 10 - 7 m = 400 n m As, ϕ 0 = h c λ - E K 1.9 = 1242 400 - E K E K = 3.1 - 1.9 e V = 1.2 e V

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