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If the work functions of three photosensitive materials are 1 eV , 2 eV and 3 eV respectively, then the ratio of the respective frequencies of light that produce photoelectrons of the maximum kinetic energy of 1 eV from each of them is

Options

  1. A1 : 2 : 3
  2. B2 : 3 : 4
  3. C1 : 1 : 1
  4. D3 : 2 : 1

Correct answer

B. 2 : 3 : 4

Step-by-step solution

From Einstein photo electric equation h v = K E + ϕ Where, ϕ = work function = h v 0 K E = 1 eV h v 1 = 1 + 1 = 2 eV h v 2 = 1 + 2 = 3 eV h v 3 = 1 + 3 = 4 eV ⇒ v 1 : v 2 : v 3 = 2 : 3 : 4

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