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On a photosensitive material, when the frequency of incident radiation is increased by 30 % , the kinetic energy of emitted photoelectrons increases from 0 . 4 eV to 0 . 9 eV . The work function of the surface is

Options

  1. A1   eV
  2. B1 . 267   eV
  3. C1 . 4   eV
  4. D1 . 8   eV

Correct answer

B. 1 . 267   eV

Step-by-step solution

h v = 0.4 + W 0 ....... (i) 1.3 h v = 0.9 + W 0 ....... (ii) (ii) - 1.3 (i) gives 0.3 W 0 = 0.9 - 1.3 ( 0.4 ) ∴ W 0 = 0.38 0.3 = 1.267 eV

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