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A photon of energy 10.2 eV corresponds to light of wavelength λ 0 . Due to an electron transition from n = 2 to n = 1 in a hydrogen atom, the light of wavelength λ is emitted. If we take into account the recoil of the atom when the photon is emitted, then

Options

  1. Aλ < λ 0
  2. Bλ > λ 0
  3. Cλ = λ 0
  4. DNone of these

Correct answer

B. λ > λ 0

Step-by-step solution

Without recoil of the atom, the entire energy is carried away by the photon. h c &#955; 0 = 10. 2 &#160; eV With recoil of the atom, energy is shared between photon and atom. So, the energy of the photon is less, hence its wavelength is more. h c &#955; &#60; h c &#955; 0 &#8756; &#955; 0 &#60; &#955;

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