For certain metal, incident frequency ν is five times threshold frequency ν 0 and the maximum velocity of the photoelectrons is 8 × 10 6 m s - 1 . If incident photon frequency is 2 ν 0 , the maximum velocity of photoelectrons will be

Step-by-step solution

According to Einstein's photoelectric equation hν = hν 0 + 1 2 mv max 2 or 1 2 mv max 2 = h ⁡ ν ⁡ - h ⁡ ν ⁡ 0 According to the given problem 1 2 m ⁡ 8 × 1 0 6 2 = h ⁡ 5 ν ⁡ 0 - ν ⁡ 0 … i 1 2 m ⁡ v max 2 = h ⁡ 2 ν ⁡ 0 - ν ⁡ 0 … i i Dividing equation ( i ) by ( ii ) 8 × 1 0 6 2 v max 2 = 4 ν ⁡ 0 ν ⁡ 0 v max 2 = 8 × 1 0 6 2 4 v max = 8 × 10 6 2 = 4 &#