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The photoelectric threshold of Tungsten is   2300   A ∘ . The energy of the electrons ejected from the surface by the ultraviolet light of wavelength 1800   A ∘ is ( h = 6.6 × 10 - 34 J   s ,   e = 1 . 6 × 10 - 19   C )

Options

  1. A0 . 15   eV
  2. B1 . 5 eV
  3. C15 eV
  4. D150 eV

Correct answer

B. 1 . 5 eV

Step-by-step solution

E k = h c e 1 λ - 1 λ 0 ( i n e V ) = 6.6 × 10 - 34 × 3 × 10 8 1.6 × 10 - 19 10 10 1800 - 10 10 2300 = 1 . 5 e V

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