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When radiation is incident on a photoelectron emitter, the stopping potential is found to be 9 V . If e m for the electron is 1.8 × 10 11 C K g - 1 , the maximum velocity the ejected electron is

Options

  1. A6 × 10 5 m s - 1
  2. B8 × 10 5 m s - 1
  3. C1.8 × 10 6 m s - 1
  4. D1.8 × 10 5 m s - 1

Correct answer

C. 1.8 × 10 6 m s - 1

Step-by-step solution

      1 2 m v m a x 2 = e V 0 ⇒         v m a x = 2 e m V 0 = 2 × 1.8 × 10 11 × 9 =   18 × 10 5   m   s - 1   =   1 .8 × 10 6   m   s - 1

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