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In a photoelectric effect measurement, the stopping potential for a given metal is found to be V 0 volt when radiation of wavelength λ 0 is used. If radiation of wavelength 2 λ 0 is used with the same metal then the stopping potential (in volt) will be

Options

  1. AV 0 2
  2. B2 V 0
  3. CV 0 + h c 2 e λ 0
  4. DV 0 - h c 2 e λ 0

Correct answer

D. V 0 - h c 2 e λ 0

Step-by-step solution

e V 0 = h c λ 0 − W 0 and e V ′ = h c 2 λ 0 − W 0 Subtracting them we have e ( V 0 − V ′ ) = h c λ 0 [ 1 − 1 2 ] = h c 2 λ 0 Or V ′ = V 0 − h c 2 e λ 0

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