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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Kinetic Theory of Gases

NTA Abhyas 2020 · Physics · Kinetic Theory of Gases

A mixture of two gasses A and B is kept in a vessel which is...

A mixture of two gasses AA and BB is kept in a vessel which is maintained at a temperature& TT. In the vessel there are NN molecules each of mass mm, of the gas AA and 2N2N molecules each of mass 2m2m of the gas BB. The mean square velocity of the molecules of the gas& BB is& v2v^{2} and the mean square velocity of the molecules of the gas& AA along the xx direction is w2w^{2}. The value of w2v2\dfrac{w2}{v2}& is

Options

  1. A2\text{2}
  2. B1\text{1}
  3. C13\dfrac{1}{3}
  4. D23\dfrac{2}{3}

Correct answer

D. 23\dfrac{2}{3}

Step-by-step solution

Mean kinetic energy of the two types of molecules should be equal. The mean square velocity of A type molecules =ω2+ω2+ω2=3ω2= {\omega}^{2} + {\omega}^{2} + {\omega}^{2} = 3{\omega}^{2}

Therefore, 12m\dfrac{1}{2}m\left(3{\omega}^{2}\right) = \dfrac{1}{2}(2m)v2\left(2m\right)v^{2}

This gives ω2v2=23\dfrac{{\omega}^{2}}{v^{2}} = \dfrac{2}{3}
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