NTA Abhyas JEE Main2020PhysicsLaws of MotionPractice
A point P moves in a counter-clockwise direction on a circular path as shown in the figure. The movement of P is such that it sweeps out a length s = t 3 + 5 where s is in metre and t is in seconds. The radius of the path is 27 m . The acceleration of P when t = 3 s is ____ m / s 2 . T a k e 13 = 3.6
Correct answer
32.40
Step-by-step solution
As s = t 3 + 5 d s d t = 3 t 2 = v ∴ a t = d v d t = 6 t a → = a c 2 + a t 2 At t = 3 s a → = v 2 R 2 + a t 2 = 9 t 4 R 2 + 6 t 2 = 27 2 + 324 = 1053 = 9 13 ∴ a → = 32.4 m / s 2