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NTA Abhyas JEE Main2020PhysicsLaws of MotionPractice

The angular velocity of a particle is ω → = 4 i ^ + j ^ - 2 k ^ about the origin. If the position vector of the particle is 2 i ^ + 3 j ^ - 3 k ^ , then its linear velocity is

Options

  1. A5 i ^ + 8 j ^ - 14 k ^
  2. B3 i ^ + 8 j ^ + 10 k ^
  3. C8 i ^ + 3 j ^ - 10 k ^
  4. D- 8 i ^ + 3 j ^ - 2 k ^

Correct answer

B. 3 i ^ + 8 j ^ + 10 k ^

Step-by-step solution

v → = ω → × r → = 3 i ^ + 8 j ^ + 10 k ^

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