A force F is applied on a block of mass 3 kg which rests on a horizontal surface with a coefficient of friction 1 2 3 . The maximum value of F for which the block doesn't move, is [Take g = 10 m s - 2 ]

Step-by-step solution

From acting on block are shown in adjoining figure As the block does not move, hence F cos ⁡ 60 ° = f = μ N = μ M g + F sin ⁡ 60 ° ∴ F 1 2 = 1 2 3 3 × 10 + F ⋅ 3 2 On simplification, we get F = 20 N