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NTA Abhyas JEE Main2020PhysicsLaws of MotionPractice

A block of mass 200   kg is being pulled by some men, up an inclined plane of inclination 45 ° and coefficient of friction 0 . 5 , as shown in the figure. If each man can apply a maximum force of 500   N , then the minimum number of men required to just slide the block, up the plane is

Options

  1. A10
  2. B7
  3. C5
  4. D9

Correct answer

C. 5

Step-by-step solution

Total force required F = m g sin ⁡ θ + f = m g sin ⁡ θ + μ s R = m g sin ⁡ θ + μ s m g cos ⁡ θ = m g ( sin ⁡ θ + μ s cos ⁡ θ ) = 200 ×9.8 ( sin ⁡ 45 ° + 0.5 cos ⁡ 45 ° ) F = 200 ×9.8 × 3 2 2 The number of men required will be 200 ×9.8 × 3 (500) × 2 2 = 4.1

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