NTA Abhyas JEE Main2020PhysicsLaws of MotionPractice
Two masses m and M are attached with strings as shown in the figure. For the system to be in equilibrium, we must have
Options
- Atan θ = 1 + 2 M m
- Btan θ = 1 - 2 m M
- Ctan θ = 1 - M 2 m
- Dtan θ = 1 + m 2 M
Correct answer
A. tan θ = 1 + 2 M m
Step-by-step solution
mg = 2 Tsin 45 ° ⇒    mg = 2 T T 1  cos θ = T cos 4 5 ∘ ⇒    T 1 cos θ = T 2 = mg 2 ...(i) Further, Mg + T  cos  4 5 ∘ = T 1  sin θ      ∵ T = mg 2 ⇒    T 1  sin θ = Mg + mg 2 1 2 ...(ii) ⇒    tan θ = Mg + mg 2 mg 2 = 1 + 2 M m dividing Eq. (ii) by Eq. (i)