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A block of mass 5 kg is placed on a rough inclined plane. The inclination of the plane is gradually increased until the block just begins to slide down. The sin of angle made by the plane with horizontal is 3 5 when the block start sliding. The coefficient of friction between the block and the plane is ( g = 10 m s - 2 )

Options

  1. A3 5
  2. B3 4
  3. C4 5
  4. D2 3

Correct answer

B. 3 4

Step-by-step solution

The block will just start sliding when the angle θ made by the inclined plane with the horizontal will be equal to the angle of repose. θ = θ repose = tan - 1 μ ⇒ tanθ = μ μ = 3 4

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