NTA Abhyas JEE Main2020PhysicsLaws of MotionPractice
A block is hanged from spring in a cage. Elongation in spring is x 1 = 4 2 mm and x 2 = 3 2 mm mm when cage moves up and down respectively with same acceleration. The expansion (in mm ) in spring when the cage moves horizontally with the same acceleration.
Correct answer
5
Step-by-step solution
x 1 = m k g + a x 2 = m k g - a x 3 = m k g 2 + a 2 ∵   x 1 2 + x 2 2 = m 2 k 2 2 g 2 + a 2 = 2 x 3 2 x 3 = x 1 2 + x 2 2 2 = 2 ( 16 + 9 ) 2 = 5