NTA Abhyas JEE Main2020PhysicsLaws of MotionPractice
A gun of mass 10 kg fires 4 bullets per second. The mass of each bullet is 20 g and the velocity of the bullet, when it leaves the gun, is 300 m s - 1 . The force required to hold the gun while firing is
Options
- A6   N
- B8   N
- C24 N
- D240   N
Correct answer
C. 24 N
Step-by-step solution
Rate of change of momentum of the bullet in forward direction = Force required to hold the gun. F = n m v = 4 × 20 × 1 0 - 3 × 300 = 24 N