NTA Abhyas JEE Main2020PhysicsLaws of MotionPractice
Coefficient of kinetic friction between 3 kg and 2 kg block is 0 . 25 . The horizontal table surface is smooth. Find the acceleration (in S.I unit) of the block of mass 10 kg .
Correct answer
6
Step-by-step solution
100 - T 2 = 10 a T 2 - T 1 - 0 . 25 × 20 = 3 a T 1 - 0 . 25 × 20 = 2 a Adding the above three equations and solving for acceleration we get a = 100 - 0.25 × 20 - 0.25 × 20 15 = 6   m   s - 2