NTA Abhyas JEE Main2020PhysicsLaws of MotionPractice
A particle of mass m is released from height h on a smooth curved surface which ends into a vertical loop of radius r , as shown. If h = 2 r , then
Options
- Athe particle reaches the top of the loop with zero velocity
- Bthe particle reaches the top of the loop with a non-zero velocity
- Cthe particle breaks off at a height h = r from base
- Dthe particle breaks off at a height r < h < 2 r
Correct answer
D. the particle breaks off at a height r < h < 2 r
Step-by-step solution
To reach the top of loop, particle must have a minimum speed of v = 5 g r at the bottom of the loop. but v 2 = 2 g h = 4 g r , so the block won't reach the highest point of the track.