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NTA Abhyas JEE Main2020PhysicsLaws of MotionPractice

In figure, a particle is placed at the highest point A of a smooth sphere of radius r . It is given slight push, and it leaves the sphere at B , at a depth h vertically below A . The value of h is

Options

  1. Ar 6
  2. B1 4 r
  3. C1 3 r
  4. D1 2 r

Correct answer

C. 1 3 r

Step-by-step solution

If v velocity acquired at B , then v 2 = 2 g h The particle will leave the sphere at B , when mv 2 r = mgcos θ 2 gh r = g . r - h r Which gives h = r 3

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