NTA Abhyas JEE Main2020PhysicsLaws of MotionPractice
A hollow vertical cylinder of radius R and height h has a smooth internal surface. A small particle is held in contact with the inner side of the upper rim at a point P . It is given a horizontal speed v 0 tangential to the rim. It leaves the lower rim at point Q , vertically below P . The number of revolutions made by the particle will be [Take acceleration due to gravity g ]
Options
- Ah 2 π R
- Bv 0 h h 2 g
- Cv 0 2 π R 2 h g
- Dv 0 π g 2 g h 2 R
Correct answer
C. v 0 2 π R 2 h g
Step-by-step solution
A hollow vertical h = 1 2 gt 2 n 2 π R = V 0 t n = V 0 2 π R 2 h g